Chloride ions treated with acidified silver nitrate yield what precipitate?

Prepare for the IGCSE Science Paper 6 Test. Utilize flashcards and multiple choice questions, complete with hints and explanations. Ace your science exam!

Multiple Choice

Chloride ions treated with acidified silver nitrate yield what precipitate?

Explanation:
When chloride ions meet silver ions in an acidic medium, they form silver chloride, which is insoluble and comes out as a solid. The reaction is Ag+ + Cl- → AgCl(s). Silver chloride is a white precipitate, so you see a white solid forming. The acid keeps the solution from making other silver compounds (like silver oxide or carbonate), so the test specifically shows the chloride. If bromide or iodide were present, you’d get different colored precipitates (cream for bromide, yellow for iodide).

When chloride ions meet silver ions in an acidic medium, they form silver chloride, which is insoluble and comes out as a solid. The reaction is Ag+ + Cl- → AgCl(s). Silver chloride is a white precipitate, so you see a white solid forming. The acid keeps the solution from making other silver compounds (like silver oxide or carbonate), so the test specifically shows the chloride. If bromide or iodide were present, you’d get different colored precipitates (cream for bromide, yellow for iodide).

Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy