What color precipitate forms when iodide ions are tested with acidified dilute nitric acid and silver nitrate?

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Multiple Choice

What color precipitate forms when iodide ions are tested with acidified dilute nitric acid and silver nitrate?

Explanation:
When testing halide ions with silver nitrate in an acidic medium, silver halides form as precipitates, and their colors differ for each halide. Iodide reacts with Ag+ to produce silver iodide, which is very insoluble and appears as a yellow precipitate. The dilute nitric acid acidifies the solution to remove interfering carbonate ions, so the test mainly shows the formation of a silver halide. If chloride were present, you’d get a white precipitate of silver chloride; if bromide, a cream-colored precipitate of silver bromide. The observed yellow precipitate therefore indicates iodide ions.

When testing halide ions with silver nitrate in an acidic medium, silver halides form as precipitates, and their colors differ for each halide. Iodide reacts with Ag+ to produce silver iodide, which is very insoluble and appears as a yellow precipitate. The dilute nitric acid acidifies the solution to remove interfering carbonate ions, so the test mainly shows the formation of a silver halide. If chloride were present, you’d get a white precipitate of silver chloride; if bromide, a cream-colored precipitate of silver bromide. The observed yellow precipitate therefore indicates iodide ions.

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