Zinc ions with sodium hydroxide yield which observation?

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Multiple Choice

Zinc ions with sodium hydroxide yield which observation?

Explanation:
When a metal ion reacts with sodium hydroxide, you often get a metal hydroxide precipitate. For zinc, the zinc ions form zinc hydroxide as a white, gelatinous solid: Zn2+ + 2 OH− → Zn(OH)2(s). In excess NaOH, this solid doesn’t stay put; it dissolves to form a complex ion, giving a colourless solution: Zn(OH)2 + 2 OH− → [Zn(OH)4]2−(aq). So the observable sequence is a white precipitate that dissolves in excess to yield a colourless solution.

When a metal ion reacts with sodium hydroxide, you often get a metal hydroxide precipitate. For zinc, the zinc ions form zinc hydroxide as a white, gelatinous solid: Zn2+ + 2 OH− → Zn(OH)2(s). In excess NaOH, this solid doesn’t stay put; it dissolves to form a complex ion, giving a colourless solution: Zn(OH)2 + 2 OH− → [Zn(OH)4]2−(aq). So the observable sequence is a white precipitate that dissolves in excess to yield a colourless solution.

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